0.333333t^2+5=8

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Solution for 0.333333t^2+5=8 equation:



0.333333t^2+5=8
We move all terms to the left:
0.333333t^2+5-(8)=0
We add all the numbers together, and all the variables
0.333333t^2-3=0
a = 0.333333; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·0.333333·(-3)
Δ = 3.999996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.999996}}{2*0.333333}=\frac{0-\sqrt{3.999996}}{0.666666} =-\frac{\sqrt{}}{0.666666} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.999996}}{2*0.333333}=\frac{0+\sqrt{3.999996}}{0.666666} =\frac{\sqrt{}}{0.666666} $

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